how can yo possibly claim that something "will be approximately 1/6th of it's (sic) weight on earth?
The gravitational acceleration on earth is roughly 9.8 m/s
2. The gravitational acceleration on the moon is approximately 1.625 m/s
2 which is around one-sixth the acceleration on earth. F = ma. So with a weaker acceleration acting upon it, a kilogram (or slug) of mass will weigh roughly one-sixth as much on the moon as it does on earth.
Earth: 1 kg * 9.8 m/s
2 = 9.8 N.
Moon: 1 kg * 1.625 m/s
2 = 1.625 N.
The moon has no atmosphere, so any volume of air would instantly dissipate around the surface of the moon, wouldn't it, still slightly attracted by the moon's gravity. Would that cubic mile still weigh 1/6th of it's (sic) weight on earth?
On the moon, that air would now occupy a volume infinitely greater than one cubic mile. It's 'weight' would be one-sixth as before. But its mass would remain unchanged - approx. 5.4 million metric tons.
A person of character and honor would apologize for his foolhardiness.
So what can we conclude when you don't?